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Como converter rapidamente data em palavras no Excel?

Em geral, geralmente convertemos a data para outros formatos de data ou dígitos no Excel, mas você já encontrou algum problema ao converter a data para palavras em inglês, conforme a imagem mostrada abaixo? Na verdade, não há nenhuma função incorporada que possa lidar com isso, exceto um código VBA.
doc data para palavras 1

Converter data em palavra com função definida


Converter data em palavra com função definida

Aqui está um código de macro que pode lhe fazer um favor na conversão de datas em palavras.

1. Habilite a folha que você usa e pressione Alt + F11 chaves para abrir Microsoft Visual Basic para Aplicações janela.

2. Clique inserção > Módulo e cole o código abaixo no script.

VBA: converter data em palavra

Function DateToWords(ByVal xRgVal As Date) As String
' Update by Extendoffice on 20240926
    Dim xYear As String
    Dim Hundreds As String
    Dim Decades As String
    Dim xTensArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    
    ' Initialize arrays
    xOrdArr = Array("First", "Second", "Third", "Fourth", "Fifth", "Sixth", _
                    "Seventh", "Eighth", "Ninth", "Tenth", "Eleventh", "Twelfth", _
                    "Thirteenth", "Fourteenth", "Fifteenth", "Sixteenth", _
                    "Seventeenth", "Eighteenth", "Nineteenth", "Twentieth", _
                    "Twenty-first", "Twenty-second", "Twenty-third", "Twenty-fourth", _
                    "Twenty-fifth", "Twenty-sixth", "Twenty-seventh", "Twenty-eighth", _
                    "Twenty-ninth", "Thirtieth", "Thirty-first")
    
    xCardArr = Array("", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", _
                    "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", _
                    "Seventeen", "Eighteen", "Nineteen")
    
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety")
    
    ' Extract year
    xYear = CStr(Year(xRgVal))
    Decades = Mid$(xYear, 3)
    
    ' Handle decades
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & xCardArr(CInt(Right$(Decades, 1)))
    End If
    
    ' Handle hundreds
    Hundreds = Mid$(xYear, 2, 1)
    If CInt(Hundreds) Then
        Hundreds = xCardArr(CInt(Hundreds)) & " Hundred "
    Else
        Hundreds = ""
    End If
    
    ' Construct English representation of the date
    DateToWords = xOrdArr(Day(xRgVal) - 1) & " " & Format$(xRgVal, "mmmm") & " " & _
                  xCardArr(CInt(Left$(xYear, 1))) & " Thousand " & Hundreds & Decades
End Function


doc data para palavras 2

3. Salve o código e volte para a planilha, selecione uma célula na qual você produzirá o resultado, digite esta fórmula = DateToWords (A2) (A2 é a data que você usa), pressione Entrar e arraste a alça de preenchimento automático sobre as células de que você precisa. Veja a imagem:
doc data para palavras 3doc data para palavras 4


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Comments (25)
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This comment was minimized by the moderator on the site
The spelling of 9th is wrong. It's written Nineth, but it should be Ninth.
This comment was minimized by the moderator on the site
Thank you for your message. I have corrected and updated the code accordingly. Thank you.
This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST NINETEEN HUNDRED NINETY EIGHT
I need dob into words in upper format but i use this micros in excel i got this
07/08/1998 SEVENTH AUGUST ONE THOUSAND NINE HUNDRED NINETY-EIGHT which is not usefull
This comment was minimized by the moderator on the site
Hi, MAX, I have modified the VBA, please try and let me know if it works. Thanks.
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(CInt(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
Hi, try this vba:
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(Fix(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
آپ کا بہت شکریہ
This comment was minimized by the moderator on the site
It is giving the #NAME? Error
This comment was minimized by the moderator on the site
I would like to add text to the output, for instance, 1958 gets converted to One Thousand Nineteen Hundred Fifty Eight and I would like it to say One Thousand Nineteen Hundred and Fifty Eight. Can someone give me an example of how I can do this please?
This comment was minimized by the moderator on the site
thank u for helping me . very useful in converting date of birth in word
This comment was minimized by the moderator on the site
Sir/Madam

It is very useful for me.

Really Amazing and helped to solve the problem within a minute.

Thank you for uploading this document. Very nice
This comment was minimized by the moderator on the site
how to use this code in vb6 for a textbox
This comment was minimized by the moderator on the site
date to word in gujarati language avilable ? please answer me. 9427909038
This comment was minimized by the moderator on the site
I think it does not work for other languages except english.
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